Tuesday, November 9, 2010

A Proof



:. C=0

I posted this a few weeks back on Twitter.  It came to me after all the media coverage on the Chilean miners and their rescue.  The proof disproves the necessity of intercessory prayer.    


Steve said...

I was sent the following message on Twitter:

"c could also equal -a or -b or some combination that equals (-a + -b)."

This is my friendly response.

My original premise in the Tweet basically used these values:

x=miners successfully rescued

:. c has no effect therefore its value is 0.

If "c could also equal -a or -b or some combination that equals (-a + -b)" is incorrect as

a+b+(-a)≠x since you need people for the rescue.
a+b+(-b)≠x since you need scientific knowledge for the rescue.

It's been awhile since I had either a math or logic course so I could still be wrong. Feel free to keep the debate open.

I should also point out that one of our contributors, Brenner (who is apparently alive), stated that:

If c=-a, then b=x and c=a=0
If c=-b, then a=x and c=b=0

So c=0. Your criteria just informs us that a or b could also=0, but prayer still does nothing.